12/(3z-3)=-20/(3z-3)^2

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Solution for 12/(3z-3)=-20/(3z-3)^2 equation:


D( z )

(3*z-3)^2 = 0

3*z-3 = 0

(3*z-3)^2 = 0

(3*z-3)^2 = 0

3*z-3 = 0 // + 3

3*z = 3 // : 3

z = 3/3

z = 1

3*z-3 = 0

3*z-3 = 0

3*z-3 = 0 // + 3

3*z = 3 // : 3

z = 3/3

z = 1

z in (-oo:1) U (1:+oo)

12/(3*z-3) = -20/((3*z-3)^2) // + -20/((3*z-3)^2)

12/(3*z-3)-(-20/((3*z-3)^2)) = 0

12/(3*z-3)+20*(3*z-3)^-2 = 0

12/(3*z-3)+20/((3*z-3)^2) = 0

(12*(3*z-3))/((3*z-3)^2)+20/((3*z-3)^2) = 0

12*(3*z-3)+20 = 0

36*z-16 = 0

(36*z-16)/((3*z-3)^2) = 0

(36*z-16)/((3*z-3)^2) = 0 // * (3*z-3)^2

36*z-16 = 0

36*z-16 = 0 // + 16

36*z = 16 // : 36

z = 16/36

z = 4/9

z = 4/9

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